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[求助]请帮我矩阵求逆

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发表于 2005-9-19 13:53:02 | 显示全部楼层 |阅读模式
<P>版主你好,最近试用了一下你的矩阵求逆函数,计算你给出的算例结果是对的,但计算下面的数据就出现:实时错误&quot;11&quot;,除数为零,错误语句为:&nbsp;&nbsp;&nbsp; add = 1 / Rect(AAA(), LLL),矩阵数据如下:</P><P>AAA(0, 0) = -0.0242<BR>AAA(0, 1) = 0.3861<BR>AAA(0, 2) = 0<BR>AAA(0, 0) = 0<BR>AAA(0, 1) = -0.4456<BR>AAA(0, 2) = 0.2156<BR>AAA(0, 0) = 0.4698<BR>AAA(0, 1) = -0.6018<BR>&nbsp;&nbsp;&nbsp; <BR>AAA(1, 0) = 0.2981<BR>AAA(1, 1) = 0.7177<BR>AAA(1, 2) = -0.7444<BR>AAA(1, 0) = -0.5221<BR>AAA(1, 1) = 0.4456<BR>AAA(1, 2) = -0.2156<BR>AAA(1, 0) = 0<BR>AAA(1, 1) = 0<BR>&nbsp;&nbsp;&nbsp; <BR>AAA(2, 0) = -0.7444<BR>AAA(2, 1) = -0.5221<BR>AAA(2, 2) = 0.7104<BR>AAA(2, 0) = -0.0769<BR>AAA(2, 1) = 0<BR>AAA(2, 2) = 0<BR>AAA(2, 0) = 0.034<BR>AAA(2, 1) = 0.599<BR>&nbsp;&nbsp;&nbsp; <BR>AAA(3, 0) = 0<BR>AAA(3, 1) = 0<BR>AAA(3, 2) = 0.3275<BR>AAA(3, 0) = 0.1156<BR>AAA(3, 1) = -0.2935<BR>AAA(3, 2) = 0.4834<BR>AAA(3, 0) = -0.034<BR>AAA(3, 1) = -0.599<BR>&nbsp;&nbsp;&nbsp; <BR>AAA(4, 0) = 0.4456<BR>AAA(4, 1) = -0.2156<BR>AAA(4, 2) = -0.2935<BR>AAA(4, 0) = 0.4834<BR>AAA(4, 1) = -0.152<BR>AAA(4, 2) = -0.2678<BR>AAA(4, 0) = 0<BR>AAA(4, 1) = 0<BR>&nbsp;&nbsp; <BR>AAA(5, 0) = -0.4456<BR>AAA(5, 1) = 0.2156<BR>AAA(5, 2) = 0<BR>AAA(5, 0) = 0<BR>AAA(5, 1) = -0.5203<BR>AAA(5, 2) = -0.3611<BR>AAA(5, 0) = 0.9659<BR>AAA(5, 1) = 0.1455<BR>&nbsp;&nbsp;&nbsp; <BR>AAA(6, 0) = 0<BR>AAA(6, 1) = 0<BR>AAA(6, 2) = -0.034<BR>AAA(6, 0) = -0.599<BR>AAA(6, 1) = 0.9659<BR>AAA(6, 2) = 0.1455<BR>AAA(6, 0) = -0.9319<BR>AAA(6, 1) = 0.4535</P><P>AAA(7, 0) = 0.4698<BR>AAA(7, 1) = -0.6018<BR>AAA(7, 2) = 0.034<BR>AAA(7, 0) = 0.599<BR>AAA(7, 1) = 0<BR>AAA(7, 2) = 0<BR>AAA(7, 0) = -0.5038<BR>AAA(7, 1) = 0.0028<BR></P><P>请高手帮我求逆,我先在此拜谢了!<BR></P><P>&nbsp;</P>
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